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PERHITUNGAN KEBUTUHAN PAGAR TINGGI
P
=
m
1
Jumlah Tiang
= (
Panjang Rintangan
- 1) x 2
3
= (
- 1) x 2
3
= buah
Keamanan
= Jumlah tiang + 10%
=
+
=
buah di bulatkan
2
Jumlah Patok
= 4 buah
3
Kawat mendatar
= Panjang rintangan x 2 x 4
= x 2 x 4
=
m
Keamanan 10%
= Kawat mendatar 10%
=
+
=
m
4
Kawat Serong
=
(Jumlah tiang - 1) x 4 x 3,5 m
=
( - 1)
x 4 x 3,5
=
x 4 x 3,5
=
m
Keamanan 10 %
=
Kawat serong + 10 %
=
+
=
m
5
Kawat mendatar/serong
=
Kawat mendatar + Kawat serong
=
+
=
m
Keamanan 10 %
=
Kawat mendatar/serong+ 10 %
=
m +
=
m