HOME
PELETON/RU
TENDA POSKO
S.MORTIR
RANPUR
HANJAR
A
KEBUTUHAN JARING TENDA PELETON
DIKETAHUI TENDA PELETON
P =
m
1. LUAS TENDA
=
(2 T x P ) 2 + (2 T x L ) 2
L
=
m
=
(2 x x ) 2 + ( 2 x x ) 2
T =
m
=
m
+
m
Jt =
bh
= m2
J =
Jaring
6,80 x 6,80
3,40 x 6,80
3,40 x 3,40
2,00 x 3,00
m
2. LUAS JARING
= m2
DIKETAHUI TENDA REGU
P =
m
3. JARING
= Luas Tenda: Luas Jaring
L
=
m
=
m
:
m
T =
m
=
x
=
Lembar
Jt =
bh
J =
Jaring
6,80 x 6,80
3,40 x 6,80
3,40 x 3,40
2,00 x 3,00
m
B
KEBUTUHAN JARING TENDA REGU
ANALISA
1. LUAS TENDA
=
(2 T x P ) 2 + (2 T x L ) 2
W =
m2/menit/org
=
(2 x x ) 2 + ( 2 x x ) 2
=
m
+
m
= m2
2. LUAS JARING
= m2
P = Panjang
L = Lebar
3. JARING
= Luas Tenda: Luas Jaring
T = Tinggi
=
m
:
m
Jt = Jumlah tenda
=
x
=
Lembar
J = Jaring
W =Waktu
C
RENCANA KEBUTUHAN KENDARAAN
1. TONASE
=
(Jrg bsr x Brt jrg) + (jrg kcl x Brt jrg)
5000 Kg
=
(
Lbr
x
Kg) + ( Lbr x Kg )
5000 Kg
=
+
5000 kg
=
5000 kg
= di bulatkan
Ran
2. VOLUME
=
(
Jrg bsr x Vol Jrg )
+
(
Jaring kcl x Vol Jrg )
8
(
Lbr
x
m3) +
( Lbr x m3 )
8
=
+
8
=
8
=
di bulatkan Ran
C
RENCANA KEBUTUHAN WAKTU
- Perorangan
=
m2
- 1 regu 10 Orang
=
m2/regu
1. TENDA TON
=
Luas tenda ton
Waktu 1 regu
=
m2
m2/Regu
=
Menit/regu
2. TENDA REGU
=
Luas tenda regu
Waktu 1 regu
=
m2
m2/Regu
= Menit/regu